【python cookbook】【数据结构与算法】2 从任意长度的可迭代对象中分解元素

Python 3.4.3 (v3.4.3:9b73f1c3e601, Feb 24 2015, 22:43:06) [MSC v.1600 32 bit (Intel)] on win32
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>>> *headdata,current=[10,3,2,6,8,5]  #*修饰的变量位于列表第一个位置，轻松分别头部和尾部
>>> headdata
[10, 3, 2, 6, 8]
>>> current
5

>>> record=('小明','xiaoming@163.com','13288888888','13566666666')
>>> name,email,*phone_numbers=record#*修饰的变量位于列表最后一个位置
>>> name
'小明'
>>> email
'xiaoming@163.com'
>>> phone_numbers
['13288888888', '13566666666']

>>> line='nobody:*:-2:-3:Unpriviledged User:/var/empty:/usr/bin/false'
>>> uname,*fields,homedir,sh=line.split(':') #*修饰的变量位于中间位置，且与字符串处理操作相结合
>>> uname
'nobody'
>>> homedir
'/var/empty'
>>> sh
'/usr/bin/false'
>>> fields
['*', '-2', '-3', 'Unpriviledged User']

>>> record=['lucy',50,123.4,(12,13,2016)]
>>> name,*_,(*_,year)=record #将某些分解出的值丢弃
>>> name
'lucy'
>>> year
2016
>>>