感谢toolic
We use Perl scripts to check if condition.
##code(t1) is as belows:
my @results=(93,4,0);
my @param_array = (
[ "50", "<", "stat1", ],
[ "1", "<", "stat2", ],
[ "3", "<", "stat3", ],
);
for ($i=0;$i<@results;$i++) {
print (" ".$results[$i]." ".$param_array[$i][1]." ".$param_array[$i][0]." ");
if ( $results[$i] + 0 < $param_array[i][0] + 0 )
{
print " beend";
}
else
{
print " end111";
}
}
The result is strange. When 95<50, if condition is not true, and it prints end111. I think the statement is right.
But when 4 < 1, if condition is not true, it also prints beend. I think the the statement is wrong.
Why does this happen?
###result is as below
perl t1
93 < 50 end111
4 < 1 beend
0 < 3 beend
fix:
You should add use warnings; to your code, and you should see warning messages like:
Unquoted string "i" may clash with future reserved word
Argument "i" isn't numeric in array element
You need to change i to $i. Change:
if ( $results[$i] + 0 < $param_array[i][0] + 0 ) {
to:
if ( $results[$i] + 0 < $param_array[$i][0] + 0 ) {
This produces the following output, which I assume is what you want (although you didn't explicitly show your expected output:
93 < 50 end111
4 < 1 beend
0 < 3 beend
