Java发送Post请求,参数JSON,接收JSON详解编程语言

public static String send(String url, JSONObject jsonObject,String encoding) throws ParseException, IOException{ String body = ""; //创建httpclient对象 CloseableHttpClient client = HttpClients.createDefault(); //创建post方式请求对象 HttpPost httpPost = new HttpPost(url); //装填参数 StringEntity s = new StringEntity(jsonObject.toString(), "utf-8"); s.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json")); //设置参数到请求对象中 httpPost.setEntity(s); System.out.println("请求地址："+url); // System.out.println("请求参数："+nvps.toString()); //设置header信息 //指定报文头【Content-type】、【User-Agent】 // httpPost.setHeader("Content-type", "application/x-www-form-urlencoded"); httpPost.setHeader("Content-type", "application/json"); httpPost.setHeader("User-Agent", "Mozilla/4.0 (compatible; MSIE 5.0; Windows NT; DigExt)"); //执行请求操作，并拿到结果（同步阻塞） CloseableHttpResponse response = client.execute(httpPost); //获取结果实体 HttpEntity entity = response.getEntity(); if (entity != null) { //按指定编码转换结果实体为String类型 body = EntityUtils.toString(entity, encoding); EntityUtils.consume(entity); //释放链接 response.close(); return body;

下面代码自己写。

原创文章，作者：Maggie-Hunter，如若转载，请注明出处：https://blog.ytso.com/17007.html

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