python 时间处理详解编程语言

在实际中遇到一个时间处理问题，需要将 Sep 06, 2014 19:30 （UTC 时间） 和 当前时间比较早晚，知道 此 2014-09-06 19:30 格式时间的运算。因此，在处理时，就想

先将sep 格式时间转化成 后面一个格式的时间样子，没有找到相关函数，于是自己简单的写了个程序，仅记于此，以备查询

代码如下：

# -*- coding: utf-8 -*- 

from datetime import date 

from datetime import datetime 

from datetime import timedelta 

# # #如果是返回当前时间，可以简单的写成 

# # time.localtime() 

# # #这个返回UTC时间 

# # time.gmtime() 

# lt = time.localtime() 

# tm = time.gmtime() 

# ft = time.strftime(%Y-%m-%d %H-%M,lt) 

# ft2 = time.strftime(%Y-%m-%d %H:%M,tm) 

# print ft, ft2 

# print -------------------------------------------------------- 

# now = datetime.datetime.now() 

# now = now.replace(day = 1) 

# print now 

# print now.time() 

# mytime = [2014-09-06 20:19] 

# #mytime2 = 2014-10-09 14:32 

# str = "".join(mytime) 

# print str 

# retime = datetime.strptime(str,%Y-%m-%d %H:%M) 

# print retime 

# retime = retime +timedelta(hours = 8) 

# print retime 

# tdtime = datetime.now() 

# print tdtime 

# if retime = tdtime - timedelta(days = 7): 

# print "too early" 

# #Sep 06, 2014 19:30 

monthdic = {Jan:01, Feb:02, Mar:03, Apr:04, May:05, Jun:06, Jul:07, Aug:08, Sep:09, Oct:10, Nov:11, Dec:12} 

def time_format(timestr): 

 timestr = timestr.replace(,,) 

 #print timestr 

 timelist = timestr.split() 

 #print timelist 

 mon = "".join(timelist[0]) 

 #print mon 

 timelist[0] = monthdic[mon] 

 #print timelist 

 mytime = "".join(timelist[2])+-+"".join(timelist[0])+-+"".join(timelist[1])+ + "".join(timelist[3]) 

 return mytime 

if __name__ == __main__: 

 timestr = Sep 06, 2014 19:30 

 str = time_format(timestr) 

 print str 

 mytime = datetime.strptime(str,%Y-%m-%d %H:%M) 

 print mytime 

 mytime = mytime +timedelta(hours = 8) 

 print mytime 

 tdtime = datetime.now() 

 print tdtime 

 if mytime = tdtime - timedelta(days = 7): 

 print "too early"

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