Java判断中文字符串是否乱码详解编程语言

private static boolean isChinese(char c) { Character.UnicodeBlock ub = Character.UnicodeBlock.of(c); if (ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS || ub == Character.UnicodeBlock.CJK_COMPATIBILITY_IDEOGRAPHS || ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_A || ub == Character.UnicodeBlock.GENERAL_PUNCTUATION || ub == Character.UnicodeBlock.CJK_SYMBOLS_AND_PUNCTUATION || ub == Character.UnicodeBlock.HALFWIDTH_AND_FULLWIDTH_FORMS) { return true; return false; public static boolean isMessyCode(String strName) { Pattern p = Pattern.compile("//s*|/t*|/r*|/n*"); Matcher m = p.matcher(strName); String after = m.replaceAll(""); String temp = after.replaceAll("//p{P}", ""); char[] ch = temp.trim().toCharArray(); float chLength = 0 ; float count = 0; for (int i = 0; i ch.length; i++) { char c = ch[i]; if (!Character.isLetterOrDigit(c)) { if (!isChinese(c)) { count = count + 1; chLength++; float result = count / chLength ; if (result 0.4) { return true; } else { return false;

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