Shell 编程(一)：Shell 变量的高级用法

#!/bin/bash
# var1 = I love you,Do you love me
var1="I love you,Do you love me";
echo "var1 = ${var1}";

# ${变量名#匹配规则} var2 = e you,Do you love me
var2=${var1#*ov}
echo "var2 = ${var2}";

# ${变量名##匹配规则} var3 = e me
var3=${var1##*ov}
echo "var3 = ${var3}";

# ${变量名%匹配规则} var4 = I love you,Do you l
var4=${var1%ov*}
echo "var4 = ${var4}";

# ${变量名%%匹配规则} var5 = I l
var5=${var1%%ov*}
echo "var5 = ${var5}";

# ${变量名/旧字符串/新字符串} var6 = I like you,Do you love me
var6=${var1/love/like}
echo "var6 = ${var6}";

# ${变量名//旧字符串/新字符串} var7 = I like you,Do you like me
var7=${var1//love/like}
echo "var7 = ${var7}";

#!/bin/bash
# 获取字符串长度
var1="Hello World"
echo "var1 = $var1"

len=${#var1}
echo "var1 len = $len"

# 通过expr获取
len=`expr length "$var1"`
echo "var1 len = $len"

# 获取字符索引位置
index=`expr index "$var1" rld`
echo "rld index = $index"

index=`expr index "$var1" a1d`
echo "a1d index = $index"

#获取子串长度(tips:匹配规则是从头开始匹配中间匹配无效)
sub_len=`expr match "$var1" rld`
echo "rld sub_len = $sub_len"

# 从 Hello 开始匹配则可成功
sub_len=`expr match "$var1" Hello`
echo "Hello sub_len = $sub_len"

# 抽取字符串中的子串
var2="redis mysql pgsql sqlserver"
echo "var2 = $var2"

# 从 var2 第 10 位开始提取子串
substr1=${var2:10}
echo "substr1 = $substr1"

# 从 var2 第 10 位开始提取长度为 5 的子串
substr2=${var2:10:5}
echo "substr2 = $substr2"

# 从 var2 的右边第 5 开始提取子串
substr3=${var2:-5}
echo "substr3 = $substr3"

substr4=${var2:(-5)}
echo "substr4 = $substr4"

# 从 var2 的右边第 5 开始提取长度为 5 的子串
substr5=${var2:-5:5}
echo "substr5 = $substr5"

# 从 5 开始,匹配长度为 10(tips:使用expr，索引计数是从1开始计算;使用${string:position}， 索引计数是从0开)
substr6=`expr substr "$var2" 5 10`
echo "substr6 = $substr6"

var1 = Hello World
var1 len = 11
var1 len = 11
rld index = 3
a1d index = 11
rld sub_len = 0
Hello sub_len = 5
var2 = redis mysql pgsql sqlserver
substr1 = l pgsql sqlserver
substr2 = l pgs
substr3 = redis mysql pgsql sqlserver
substr4 = erver
substr5 = redis mysql pgsql sqlserver
substr6 = s mysql pg

#!/bin/bash
string="Bigdata process framework is Hadoop , Hadoop is an open source project"

# 打印文字
function print_tips {
  echo "-----------------------------"
  echo "(1).打印 string 长度"
  echo "(2).删除字符串中所有的 Hadoop"
  echo "(3).替换第一个 Hadoop 为 Mapreduce"
  echo "(4).替换全部 Hadoop 为 Mapreduce"
  echo "-----------------------------"
}

# 打印 string 长度
function len_of_string {
  echo ${#string}
}

# 删除字符串中所有的 Hadoop
function del_hadoop {
  echo ${string//Hadoop/}
}

# 替换第一个 Hadoop 为 Mapreduce
function rep_hadoop_mapreduce_first {
  echo ${string/Hadoop/mapreduce}
}

# 替换全部 Hadoop 为 Mapreduce
function rep_hadoop_mapreduce_all {
  echo ${string//Hadoop/mapreduce}
}

# 主程序
while true; do
  echo "[string=$string]"
  print_tips
  read -p "Pls input you choice(1|2|3|4|q|Q)：" choice
  case $choice in
  1)
    len_of_string
    ;;
  2)
    del_hadoop
    ;;
  3)
    rep_hadoop_mapreduce_first
    ;;
  4)
    rep_hadoop_mapreduce_all
    ;;
  q | Q)
    exit
    ;;
  *)
    echo "Error, input only in(1|2|3|4|q|Q)"
    ;;
  esac
  echo "-----------------------------"
done

#!/bin/bash
index=1
for user in `cat /etc/passwd |cut -d ":" -f 1`
do
        echo "This is $index user: $user"
        index=$(($index+1))
done

This is 1 user: root
This is 2 user: bin
This is 3 user: daemon
This is 4 user: adm
This is 5 user: lp
This is 6 user: sync
This is 7 user: shutdown
This is 8 user: halt
This is 9 user: mail
This is 10 user: operator
This is 11 user: games
This is 12 user: ftp
This is 13 user: nobody
This is 14 user: systemd-network
This is 15 user: dbus
This is 16 user: polkitd
This is 17 user: sshd
This is 18 user: postfix
This is 19 user: chrony
This is 20 user: nscd
This is 21 user: tcpdump
This is 22 user: ntp
This is 23 user: www
This is 24 user: redis
This is 25 user: openvpn
This is 26 user: emqx
This is 27 user: epmd

#!/bin/bash
echo "This is $(date +%Y) year";
echo "This is $(($(date +%Y)+1)) year";

This is 2022 year
This is 2023 year

# example.sh
echo "This year have passed $(date +%j) days";
echo "This year have passed $(date +%V) weeks";
echo "There is $((365-$(date +%j))) days before new year";
echo "There is $(((365-$(date +%j))/7)) weeks before new year";

This year have passed 363 days
This year have passed 52 weeks
There is 2 days before new year
There is 0 weeks before new year

#!/bin/bash

nginx_process_num=$(ps -ef|grep nginx|grep -v grep|wc -l)
if [ $nginx_process_num -eq 0 ];then
    systemctl start nginx
fi

# example.sh
string="Hello world";
declare -r string
echo "string = $string"

# 再次赋值将无法修改
string="zxcvadsf"
echo "string = $string"

string = Hello world
example7.sh: line 7: string: readonly variable
string = Hello world

# example.sh
num1=100
num2=10
num3=$num1+$num2
echo $num3

declare -i num3
num3=$num1+$num2
echo "num3 = $num3"

num3 = 100+10
num3 = 110

declare -f
declare -F

# example7.sh
echo $num4

# bash
> declare -x num4=122

# example7.sh
echo $num4

#第一行为空
122

# example.sh
declare -a array
array=("jones" "mike" "kobe" "jordan")
echo "array = ${array[@]}"
echo "array[0] = ${array[0]}"
echo "array[1] = ${array[1]}"
echo "array length = ${#array[@]}"

for v in ${array[@]}
do
    echo $v
done

array = jones mike kobe jordan 
array[0] = jones
array[1] = mike
array length = 4
jones
mike
kobe
jordan

# example.sh
#!/bin/bash
while true
do
  read -p "pls input a positive number :" num
  expr $num + 1 &> /dev/null
  if [ $? -eq 0 ]; then
    if [ `expr $num \> 0` -eq 1 ]; then
      for ((i = 1; i <= $num; i++))
      do
        sum=`expr $sum + $i`
      done
      echo "1+2+3...+$num = $sum"
      exit
    fi
  fi
  echo "error, input enlegal"
  continue
done

> sh example9.sh 
pls input a positive number :10
1+2+3...+10 = 55

> bc
bc 1.06.95
Copyright 1991-1994, 1997, 1998, 2000, 2004, 2006 Free Software Foundation, Inc.
This is free software with ABSOLUTELY NO WARRANTY.
For details type `warranty'. 

scale=4
23.444/5.2
4.5084
3.56+35.4
38.96