2022-11-15：这里有 n 个航班，它们分别从 1 到 n 进行编号。有一份航班预订表 bookings ，表中第 i 条

use std::iter::repeat;

impl Solution {
    pub fn corp_flight_bookings(bookings: Vec<Vec<i32>>, n: i32) -> Vec<i32> {
        // 1 2 3 4 n
        // 0 1 2 3 .. n n+1
        let mut cnt: Vec<i32> = repeat(0).take((n + 2) as usize).collect();
        for book in bookings.iter() {
            // start book[0]
            // end   book[1]
            // 票    book[2]
            cnt[book[0] as usize] += book[2];
            cnt[(book[1] + 1) as usize] -= book[2];
        }
        for i in 1..cnt.len() {
            cnt[i] += cnt[i - 1];
        }
        let mut ans: Vec<i32> = repeat(0).take(n as usize).collect();
        for i in 0..n {
            ans[i as usize] = cnt[(i + 1) as usize];
        }
        return ans;
    }
}

fn main() {
    let b = vec![vec![1, 2, 10], vec![2, 3, 20], vec![2, 5, 25]];
    let n = 5;
    let ans = Solution::corp_flight_bookings(b, n);
    println!("ans = {:?}", ans);
}

struct Solution {}