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linux无限刷屏代码,linux下如何实现简单刷屏

Linux代码 实现 如何 简单 无限 刷屏
2023-06-13 09:11:18 时间

大家好,又见面了,我是你们的朋友全栈君。

今天为了测试我的LCD有没有坏点写了一个简单的刷屏程序,效果还不错,分析给大家。代码如下:

#include

#include

#include

#include

#include

#include

#include

#include

int main(int argc,char *argv[])

{

int fbfd = 0;

struct fb_var_screeninfo vinfo;

struct fb_fix_screeninfo finfo;

long int screensize = 0;

char *fbp = 0;

char inbuf[240*320*2];

int i = 0;

/*open /dev/fb0 */

fbfd = open(“/dev/fb0”,O_RDWR);

if(fbfd<=0)

{

printf(“Error:cannot open framebuffer devices./n”);

return -1;

}

printf(“The framebuffer devices was opened successfully./n”);

/*get framebuffer infomation*/

if(ioctl(fbfd,FBIOGET_FSCREENINFO,&finfo))

{

printf(“Error: reanding fixed informatin./n”);

return -1;

}

if(ioctl(fbfd,FBIOGET_VSCREENINFO,&vinfo))

{

printf(“Error: reanding var informatin./n”);

return -1;

}

/*set screensiez*/

screensize = vinfo.xres*vinfo.yres*vinfo.bits_per_pixel/8;

/*mmap*/

fbp = (char*)mmap(0,screensize,PROT_READ|PROT_WRITE,MAP_SHARED,fbfd,0);

if((int)fbp == -1)

{

printf(“Error: failed to map framebuffer device to memory./n”);

return -4;

}

printf(” The framebuffer device was mapped to memory sucessfully./n”);

memcpy(inbuf,fbp,screensize);//保存刷屏前显存中的数据

for(i = 0;i<0xff;i++)

{

memset(fbp,i,screensize);

sleep(1);

}

memcpy(fbp,inbuf,screensize);//将保存的显存数据复原回去

munmap(fbp,screensize);

printf(“The framebuffer device was munmaped successfully./n”);

close(fbfd);

printf(“The framebuffer device was closed successfully./n”);

return 0;

}

发布者:全栈程序员栈长,转载请注明出处:https://javaforall.cn/136720.html原文链接:https://javaforall.cn