SQL 经典五十道题
--1.学生表
Student(S,Sname,Sage,Ssex) --S 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别
--2.课程表
Course(C,Cname,T) --C --课程编号,Cname 课程名称,T 教师编号
--3.教师表
Teacher(T,Tname) --T 教师编号,Tname 教师姓名
--4.成绩表
SC(S,C,score) --S 学生编号,C 课程编号,score 分数
*/
--创建测试数据
create table Student(S varchar(10),Sname varchar(10),Sage datetime,Ssex nvarchar(10)) insert into Student values(01 , 赵雷 , 1990-01-01 , 男) insert into Student values(02 , 钱电 , 1990-12-21 , 男) insert into Student values(03 , 孙风 , 1990-05-20 , 男) insert into Student values(04 , 李云 , 1990-08-06 , 男) insert into Student values(05 , 周梅 , 1991-12-01 , 女) insert into Student values(06 , 吴兰 , 1992-03-01 , 女) insert into Student values(07 , 郑竹 , 1989-07-01 , 女) insert into Student values(08 , 王菊 , 1990-01-20 , 女) create table Course(C varchar(10),Cname,varchar(10),T varchar(10)) insert into Course values(01 , 语文 , 02) insert into Course values(02 , 数学 , 01) insert into Course values(03 , 英语 , 03) create table Teacher(T varchar(10),Tname,varchar(10)) insert into Teacher values(01 , 张三) insert into Teacher values(02 , 李四) insert into Teacher values(03 , 王五) create table SC(S varchar(10),C varchar(10),score decimal(18,1)) insert into SC values(01 , 01 , 80) insert into SC values(01 , 02 , 90) insert into SC values(01 , 03 , 99) insert into SC values(02 , 01 , 70) insert into SC values(02 , 02 , 60) insert into SC values(02 , 03 , 80) insert into SC values(03 , 01 , 80) insert into SC values(03 , 02 , 80) insert into SC values(03 , 03 , 80) insert into SC values(04 , 01 , 50) insert into SC values(04 , 02 , 30) insert into SC values(04 , 03 , 20) insert into SC values(05 , 01 , 76) insert into SC values(05 , 02 , 87) insert into SC values(06 , 01 , 31) insert into SC values(06 , 03 , 34) insert into SC values(07 , 02 , 89) insert into SC values(07 , 03 , 98)
--1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数
SELECT a.* ,c.* from (select a.* from (SELECT * from sc WHERE sc.C in(01))a left JOIN(SELECT * from sc where sc.C in(02))b ON a.s =b.s where a.score b.score ) a ,student c where a.s =c.s;
--2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
SELECT a.* ,c.* (SELECT a.* (SELECT * FROM sc WHERE sc.C in(01))a LEFT JOIN(SELECT * FROM sc WHERE sc.C in(02))b ON a.s =b.s WHERE a.score b.score) a,student c WHERE a.s =c.s
--3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
SELECT ,c.Sname ,b.avgscore (SELECT a.s s , avg(a.score) avgscore FROM sc a GROUP BY a.s) b ,student c WHERE b.avgscore 60 AND c.s =b.s
--4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
SELECT ,c.Sname ,b.avgscore (SELECT a.s s , avg(a.score) avgscore FROM sc a GROUP BY a.s) b ,student c WHERE b.avgscore 60 AND c.s =b.s
--5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
SELECT ,c.Sname ,b.num ,b.sumscore FROM (SELECT a.s s ,COUNT(a.c) num ,SUM(a.score) sumscore FROM sc a GROUP BY a.s) b ,student c WHERE b.s =c.s
--6、查询"李"姓老师的数量
SELECT COUNT(a.Tname) (SELECT Tname Tname teacher WHERE Tname LIKE 李%) a
--7、查询学过"张三"老师授课的同学的信息
SELECT student d ,sc e WHERE e.S =d.S (SELECT teacher a ,course b WHERE a.T =b.T AND a.Tname=张三)
--8、查询没学过"张三"老师授课的同学的信息
SELECT student a WHERE a.S NOT in (SELECT ,student b WHERE a.S=b.S AND a.C = (SELECT b.c teacher a ,course b WHERE a.T =b.T AND a.Tname =张三))
--9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息
SELECT FROM sc a, sc b, student c WHERE a.S =b.S AND a.C=01 and b.C=02 AND c.S =a.S
--10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息
SELECT student a WHERE a.S in SELECT DISTINCT(sc.s) WHERE SELECT S FROM sc WHERE sc.C in(02) GROUP BY sc.S) )
--11、查询没有学全所有课程的同学的信息
SELECT student b WHERE b.S in SELECT (SELECT a.S s ,COUNT(a.C) NUM GROUP BY a.s) a WHERE a.NUM 3 )
--12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息
SELECT student e WHERE e.S in (SELECT DISTINCT(c.s) student c ,sc d WHERE c.s=d.s d.C in (SELECT FROM student a ,sc b WHERE a.s =b.s AND a.s =01 )
--13、查询和"01"号的同学学习的课程完全相同的其他同学的信息
SELECT sc a WHERE a.S =01 SELECT (SELECT ,COUNT(b.c) num student a ,sc b WHERE a.s=b.S GROUP BY WHERE a.num=3 AND a.s 01
--14、查询没学过"张三"老师讲授的任一门课程的学生姓名
SELECT student a WHERE a.S NOT in SELECT SELECT ,b.Cname teacher a ,course b WHERE a.T=b.T a.Tname=张三 ,sc b WHERE a.c=b.C )
--15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
SELECT ,b.Sname ,a.avgscore (SELECT AVG(score) avgscore WHERE sc.score 60 GROUP BY HAVING COUNT(s) =2) a ,student b WHERE a.S=b.S
--16、检索"01"课程分数小于60,按分数降序排列的学生信息
SELECT (SELECT a.s s WHERE a.C =01 a.score 60 ORDER BY a.score DESC ,student b WHERE a.s=b.S
--17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
SELECT (SELECT ,b.score ,c.avgscore LEFT JOIN (SELECT ,AVG(a.score) avgscore GROUP BY a.S) c ON c.S =b.S) a ,student b WHERE a.S =b.S ORDER BY avgscore DESC
--18、查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
--及格为 =60,中等为:70-80,优良为:80-90,优秀为: =90
SELECT ,b.Cname ,MAX(a.score) ,MIN(a.score) ,AVG(a.score) ,(SELECT COUNT(1) FROM sc WHERE sc.C=b.C and score 60)/(SELECT COUNT(1)FROM sc WHERE sc.C=b.c ) jigelv FROM sc a ,course b WHERE a.C =b.C GROUP BY a.C
SELECT ,a.Cname ,MAX(b.score) ,MIN(b.score) ,CAST(AVG(b.score) AS DECIMAL(18,2)) pingqunfen ,CAST((SELECT COUNT(1) FROM sc WHERE sc.C=a.C AND sc.score 60)/ (SELECT COUNT(1) FROM sc WHERE sc.C =a.C) AS DECIMAL(18,2)) jigelv ,CAST((SELECT COUNT(1) FROM sc WHERE sc.C =a.c AND sc.score =70 AND sc.score 80)/ (SELECT COUNT(1) FROM sc WHERE sc.c =a.c) AS DECIMAL (18,2)) youlianlv course a,sc b WHERE a.C=b.C GROUP BY a.C,a.Cname ORDER BY a.C DESC
--19、按各科成绩进行排序,并显示排名
SELECT ,c.sname ,b.cname ,a.score ,(SELECT COUNT(1) FROM sc WHERE sc.C=a.c AND sc.score a.score)+1 mc FROM sc a ,course b,student c WHERE a.c=01 AND a.c=b.c AND a.s=c.s ORDER BY mc
SELECT ,c.sname ,b.cname ,a.score ,(SELECT COUNT(1) FROM sc WHERE sc.C=a.c AND sc.score a.score)+1 mc FROM sc a ,course b,student c WHERE a.c=02 AND a.c=b.c AND a.s=c.s ORDER BY mc
SELECT ,c.sname ,b.cname ,a.score ,(SELECT COUNT(1) FROM sc WHERE sc.C=a.c AND sc.score a.score)+1 mc FROM sc a ,course b,student c WHERE a.c=03 AND a.c=b.c AND a.s=c.s ORDER BY mc
--20、查询学生的总成绩并进行排名
SELECT ,b.sumscore ,@rownum:=@rownum +1 AS rownum (SELECT a.s s ,SUM(a.score) sumscore GROUP BY ORDER BY sumscore DESC ) as b ,(SELECT @rownum:=0)r
--21、查询不同老师所教不同课程平均分从高到低显示
SELECT c.Tname ,b.Cname ,AVG(a.score) ,course b ,teacher c WHERE a.C =b.C AND b.T =c.T GROUP BY a.C ORDER BY AVG(a.score) DESC
--22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
SELECT (SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=01AND a.score b.score)+1 mc FROM sc b WHERE b.c=01 HAVING mc BETWEEN 2 AND 3 UNION ALL SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=02AND a.score b.score)+1 mc FROM sc b WHERE b.c=02 HAVING mc BETWEEN 2 AND 3 UNION ALL SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=03AND a.score b.score)+1 mc FROM sc b WHERE b.c=03 HAVING mc BETWEEN 2 AND 3 ,student b WHERE a.s =b.s
--23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比
SELECT (SELECT c.Cname ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.C=01) 85以上 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.score 70 AND a.C=01) [70_85] ,(SELECT COUNT(*)FROM sc a WHERE a.score 70 AND a.C=b.c AND c.c=a.C AND a.score 60 AND a.C=01) [60_70] ,(SELECT COUNT(*)FROM sc a WHERE a.score 60 AND a.C=b.c AND c.c=a.C AND a.C=01) 60一下 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.C=01)/(SELECT COUNT(*)FROM sc WHERE c=01AND C=b.c AND c.c=c) 85以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.score 70 AND a.C=01)/(SELECT COUNT(*)FROM sc WHERE c=01AND C=b.c AND c.c=c) [70_85]以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 70 AND a.C=b.c AND c.c=a.C AND a.score 60 AND a.C=01)/(SELECT COUNT(*)FROM sc WHERE c=01AND C=b.c AND c.c=c)[60_70]以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 60 AND a.C=b.c AND c.c=a.C AND a.C=01)/(SELECT COUNT(*)FROM sc WHERE c=01AND C=b.c AND c.c=c)60以上比率 FROM sc b ,course c WHERE b.c=c.c AND c.c=01 UNION ALL SELECT c.Cname ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.C=02) 85以上 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.score 70 AND a.C=02) [70_85] ,(SELECT COUNT(*)FROM sc a WHERE a.score 70 AND a.C=b.c AND c.c=a.C AND a.score 60 AND a.C=02) [60_70] ,(SELECT COUNT(*)FROM sc a WHERE a.score 60 AND a.C=b.c AND c.c=a.C AND a.C=02) 60一下 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.C=02)/(SELECT COUNT(*)FROM sc WHERE c=02AND C=b.c AND c.c=c) 85以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.score 70 AND a.C=02)/(SELECT COUNT(*)FROM sc WHERE c=02AND C=b.c AND c.c=c)[70_85]以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 70 AND a.C=b.c AND c.c=a.C AND a.score 60 AND a.C=02)/(SELECT COUNT(*)FROM sc WHERE c=02AND C=b.c AND c.c=c)[60_70]以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 60 AND a.C=b.c AND c.c=a.C AND a.C=02)/(SELECT COUNT(*)FROM sc WHERE c=02AND C=b.c AND c.c=c)60以上比率 FROM sc b ,course c WHERE b.c=c.c AND c.c=02 UNION ALL SELECT c.Cname ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.C=03) 85以上 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.score 70 AND a.C=03) [70_85] ,(SELECT COUNT(*)FROM sc a WHERE a.score 70 AND a.C=b.c AND c.c=a.C AND a.score 60 AND a.C=03) [60_70] ,(SELECT COUNT(*)FROM sc a WHERE a.score 60 AND a.C=b.c AND c.c=a.C AND a.C=03) 60一下 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.C=03)/(SELECT COUNT(*)FROM sc WHERE c=03AND C=b.c AND c.c=c) 85以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 85 AND a.C=b.c AND c.c=a.C AND a.score 70 AND a.C=03)/(SELECT COUNT(*)FROM sc WHERE c=03AND C=b.c AND c.c=c)[70_85]以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 70 AND a.C=b.c AND c.c=a.C AND a.score 60 AND a.C=03)/(SELECT COUNT(*)FROM sc WHERE c=03AND C=b.c AND c.c=c)[60_70]以上比率 ,(SELECT COUNT(*)FROM sc a WHERE a.score 60 AND a.C=b.c AND c.c=a.C AND a.C=01)/(SELECT COUNT(*)FROM sc WHERE c=03AND C=b.c AND c.c=c)60以上比率 FROM sc b ,course c WHERE b.c=c.c AND c.c=03) a
--24、查询学生平均成绩及其名次
SELECT ,a.avgscore ,@rownum:=@rownum +1 AS rownum FROM (SELECT ,AVG(score) avgscore GROUP BY s ORDER BY avgscore DESC ,(SELECT @rownum:=0)r
--25、查询各科成绩前三名的记录
SELECT (SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=01AND a.score b.score)+1 mc FROM sc b WHERE b.c=01 HAVING mc BETWEEN 1 AND 3 UNION ALL SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=02AND a.score b.score)+1 mc FROM sc b WHERE b.c=02 HAVING mc BETWEEN 1 AND 3 UNION ALL SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=03AND a.score b.score)+1 mc FROM sc b WHERE b.c=03 HAVING mc BETWEEN 1 AND 3 ,student b WHERE a.s =b.s
--26、查询每门课程被选修的学生数
SELECT a.Cname ,COUNT(b.c) FROM sc b,course a WHERE a.c =b.c GROUP BY b.c
--27、查询出只有两门课程的全部学生的学号和姓名
SELECT ,b.Sname ,a.countc (SELECT ,COUNT(c) countc FROM GROUP BY s HAVING countc =2) a ,student b WHERE a.s=b.s
--28、查询男生、女生人数
select s.Ssex,COUNT(*)from student s where s.Ssex=男 UNION select s.Ssex,COUNT(*)from student s where s.Ssex=女
--29、查询名字中含有"风"字的学生信息
SELECT ,count(*) FROM student WHERE Sname rLIKE 风
--30、查询同名同性学生名单,并统计同名人数
SELECT s.Sname ,s.Ssex ,COUNT(*) countnum student s GROUP BY s.Sname,s.Ssex HAVING countnum =2
--31、查询1990年出生的学生名单(注:Student表中Sage列的类型是datetime)
SELECT student WHERE Sage LIKE 1990%
--32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号
SELECT a.Cname ,AVG(sc.score) avgscore FROM sc ,course a WHERE sc.C =a.C GROUP BY sc.C ORDER BY avgscore DESC
--33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩
SELECT (SELECT a.Sname ,AVG(sc.score) avgscore FROM sc ,student a WHERE sc.s =a.s GROUP BY sc.s ORDER BY avgscore DESC WHERE a.avgscore 85
--34、查询课程名称为"数学",且分数低于60的学生姓名和分数
SELECT sc a,course b WHERE a.c =b.c AND b.Cname=数学 AND a.score 60
--35、查询所有学生的课程及分数情况;
SELECT student a ,course b ,sc c WHERE a.S=c.S AND b.C =c.C
--36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;
SELECT b.Sname ,c.Cname ,a.score sc a, student b,course c WHERE a.score 70 AND a.C =c.C AND a.S =b.S
--37、查询不及格的课程
SELECT b.Sname ,c.Cname ,a.score sc a, student b,course c WHERE a.score 60 AND a.C =c.C AND a.S =b.S
--38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名;
SELECT ,c.Sname ,a.Cname ,b.score course a ,sc b ,student c WHERE a.C =b.C AND b.score =80 AND c.S =b.S AND a.C=01
--39、求每门课程的学生人数
SELECT b.Cname ,COUNT(a.c) sc a ,course b WHERE b.c=a.C GROUP BY a.C
--40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩
SELECT ,MAX(c.score) teacher a,student b ,sc c ,course d WHERE a.T =d.T AND d.C =c.C AND c.S =b.S AND a.Tname =张三
--41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
SELECT c.* FROM sc c GROUP BY c.`C`,c.`score` HAVING COUNT(*)
--42、查询每门功成绩最好的前两名
SELECT (SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=01AND a.score b.score)+1 mc FROM sc b WHERE b.c=01 HAVING mc BETWEEN 1 AND 2 UNION ALL SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=02AND a.score b.score)+1 mc FROM sc b WHERE b.c=02 HAVING mc BETWEEN 1 AND 2 UNION ALL SELECT b.s ,b.C ,b.score ,(SELECT COUNT(*) FROM sc a WHERE a.c=03AND a.score b.score)+1 mc FROM sc b WHERE b.c=03 HAVING mc BETWEEN 1 AND 2 ,student b WHERE a.s =b.s
--43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列
SELECT ,b.Cname ,COUNT(a.C) countc sc a,course b WHERE a.c=b.C GROUP BY HAVING countc 5 ORDER BY countc DESC
--44、检索至少选修两门课程的学生学号
SELECT ,COUNT(sc.C) countc GROUP BY sc.S HAVING countc =2
--45、查询选修了全部课程的学生信息
SELECT ,COUNT(sc.C) countc sc ,student a WHERE sc.S =a.S GROUP BY sc.S HAVING countc =3
--46、查询各学生的年龄
SELECT s.s, s.sname, EXTRACT(YEAR FROM NOW())-EXTRACT(YEAR FROM s.sage) 年龄 student s
--47、查询本周过生日的学生
SELECT ,s.Sname ,s.Sage FROM student s WHERE YEARWEEK(DATE_FORMAT(s.Sage,%Y-%m-%d)) =YEARWEEK(NOW())
--48、查询下周过生日的学生
SELECT ,s.Sname ,s.Sage FROM student s WHERE YEARWEEK(DATE_FORMAT(s.Sage,%Y-%m-%d)) =YEARWEEK(NOW())+1
--49、查询本月过生日的学生
SELECT ,s.Sname ,s.Sage FROM student s WHERE MONTH(DATE_FORMAT(s.Sage,%Y-%m-%d)) =MONTH(NOW())
--50、查询下月过生日的学生
SELECT ,s.Sname ,s.Sage FROM student s WHERE MONTH(DATE_FORMAT(s.Sage,%Y-%m-%d)) =MONTH(NOW())+1其中有三四个题做的不尽人意勉强实现需求
最强最全面的大数据SQL经典面试题(由31位大佬共同协作完成)(四) 本套SQL题的答案是由许多小伙伴共同贡献的,1+1的力量是远远大于2的,有不少题目都采用了非常巧妙的解法,也有不少题目有多种解法。本套大数据SQL题不仅题目丰富多样,答案更是精彩绝伦!
最强最全面的大数据SQL经典面试题(由31位大佬共同协作完成)(三) 本套SQL题的答案是由许多小伙伴共同贡献的,1+1的力量是远远大于2的,有不少题目都采用了非常巧妙的解法,也有不少题目有多种解法。本套大数据SQL题不仅题目丰富多样,答案更是精彩绝伦!
最强最全面的大数据SQL经典面试题(由31位大佬共同协作完成)(二) 本套SQL题的答案是由许多小伙伴共同贡献的,1+1的力量是远远大于2的,有不少题目都采用了非常巧妙的解法,也有不少题目有多种解法。本套大数据SQL题不仅题目丰富多样,答案更是精彩绝伦!
最强最全面的大数据SQL经典面试题(由31位大佬共同协作完成)(一) 本套SQL题的答案是由许多小伙伴共同贡献的,1+1的力量是远远大于2的,有不少题目都采用了非常巧妙的解法,也有不少题目有多种解法。本套大数据SQL题不仅题目丰富多样,答案更是精彩绝伦!
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