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代码思考题玩玩

代码
2023-09-11 14:15:23 时间

题目一：

思路参考：参考

传入一个从0开始顺序数组，每个数差值不同。从第一个元素依次往后跳，
每次跳跃只能跳前与前一次跳跃差值k的k-1、k或k+1个单位。输出传入的数组能否成功跳到终点。

示例 1:
[0,1,3,5,6,8,12,17]
返回 true。

即可以成功通过，按照如下方案跳跃：
跳1个单位到第2项1, 然后跳2个单位到第3项3, 接着
跳2个单位到第4项5, 然后跳3个单位到第6项8,
跳4个单位到第7项12, 最后，跳5个单位到第8项17。

示例 2:
[0,1,2,3,4,8,9,11]
返回 false。

没有办法到终点。
这是因为第5和第6项之间的间距太大，从2跳到4后，只能再最大跳3格，到不了8。

自己分析：

1. 升序（非负数）
2. 第一位永远是0
3. 初始第一步假设为1

 

# Py (有待修订)

#!/usr/bin/env python
# -*- coding:utf-8 -*-
# __author__ = "loki"

"""
[0, 1, 3, 5, 6, 8, 12, 17]
[0, 1, 2, 3, 4, 8, 9, 11]
数组跳跃
"""

userInput = [0, 1, 3, 5, 6, 8, 12, 17]
userInput2 = [0, 1, 2, 3, 4, 8, 9, 11]
userInput3 = [3, 2, 1, 0, 4]


def number_jump(user_list):
    # max_pos 为最列表远长度初始值
    # length 为列表长度
    length, max_pos = len(user_list), 0

    for i in range(length):
        if max_pos == 0:
            max_pos += 1
        if i <= max_pos:
            max_pos = max(i + user_list[i], max_pos)
            # print(i, user_list[i], max_pos)
            if max_pos >= length - 1:
                return True
    return False


def main():
    print("情况一", number_jump(userInput))
    print("情况二", number_jump(userInput2))
    print("情况三", number_jump(userInput3))


if __name__ == '__main__':
    main()
View Code

# Js

 1 var canCross = function (stones) {
 2     // 确定状态
 3     let ability = new Array(stones.length)  // 存每一个单元格是否有解
 4     let step = {}   //  存跳到每一个单元格的步跳跃距离可能性
 5     
 6     // 初始化数据
 7     ability[0] = true
 8     step[stones[0]] = new Set().add(0)  
 9 
10     // 第二个单位格开始遍历
11     for (let i = 1; i < ability.length; i++) {
12 
13         ability[i] = false
14         step[stones[i]] = new Set()
15         for (let j = 0; j < i; j++) {
16             for (let k of step[stones[j]]) {
17                 if (ability[j] && (stones[i] - stones[j] >= k - 1 && stones[i] - stones[j] <= k + 1)) {
18                     ability[i] = true
19                     // 存储所有可以到达该单元格的步数
20                     step[stones[i]].add(stones[i] - stones[j])
21                 }
22             }
23         }
24     }
25     // 返回最后一个点是否到达情况
26     return ability[ability.length - 1]
27 };
28 document.write('[0,1,3,5,6,8,12,17]'+'：'+canCross([0,1,3,5,6,8,12,17])+'</br>')
29 document.write('[0,1,2,3,4,8,9,11]'+'：'+canCross([0,1,2,3,4,8,9,11])+'</br>')
View Code

 

 

题目二：

写一个JS函数，传入一个一维数组表示1只股票每日收盘股价，输出可获得最大收益的一次买入与卖出时间点。
例：
输入： [4,5,3,5,6,8,6,3,2,5]
输出：第3天买入 第6天卖出 收益5

 

# Js

 1       let list = [7, 7, 8, 3, 6, 2, 3, 3];
 2       let list2 = [4, 5, 3, 5, 6, 8, 6, 3, 2, 5];
 3       function getMaxValue(arr) {
 4         let maxEarnings = 0; //最大收益
 5         let min, max;
 6         for (let i = 0; i < arr.length; i++) {
 7           for (let j = i + 1; j < arr.length; j++) {
 8             if (arr[j] - arr[i] > maxEarnings) {
 9               maxEarnings = arr[j] - arr[i];
10               min = i;
11               max = j;
12             }
13           }
14         }
15         return `第${min + 1}天买入，第${max +
16           1}天卖出，最大收益是${maxEarnings}`;
17       }
18       console.log(getMaxValue(list));
19       console.log(getMaxValue(list2));
View Code

# Js（带样式）

 1 <!DOCTYPE html>
 2 <html lang="zh">
 3 <head>
 4     <meta charset="UTF-8">
 5     <meta name="viewport" content="width=device-width, initial-scale=1.0">
 6     <meta http-equiv="X-UA-Compatible" content="ie=edge">
 7     <title></title>
 8     <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js" type="text/javascript" charset="utf-8"></script>
 9     <script src="https://cdn.jsdelivr.net/npm/vue/dist/vue.js"></script>
10 </head>
11 <body>
12     <div id="app">
13         <input type="text" v-model="gp" style="width: 550px;">
14         <span style="color: red;">输入股票价格','分割</span>
15         <div v-for="sy in shouyi">
16             <span>第{{sy.s}}天-第{{sy.e}}天，收益{{sy.y}}</span>
17         </div>
18     </div>
19     <script type="text/javascript">
20         let app = new Vue({
21             el: "#app",
22             data: {
23                 gp: '6,4,5,6,7,12,56,24',
24                 shouyi:[]
25             },
26             watch: {
27                 gp(newValue, oldValue) {
28                     this.shouyi = []
29                     let arr = this.gp.split(',')
30                     // console.log(arr)
31                     this.findMax(arr)
32                 }
33             },
34             methods: {
35                 findMax(arr) {
36                     let $this = this
37                     _.forEach(arr,function(value, key){
38                         if(key>0){
39                             let prev_arr = arr.slice(0,key)
40                             let prev_arr_min = _.minBy(prev_arr,function(o){return parseInt(o)})
41                             //最小值index                            
42                             if(value-prev_arr_min>0){
43                                 let min_arr = $this.findIndx(prev_arr,prev_arr_min)
44                                 $this.shouyi.push({s:min_arr,e:key+1,y:value-prev_arr_min})
45                                 $this.shouyi = _.sortBy($this.shouyi, ['y']).reverse();
46                                 console.log('第'+min_arr+'天买入，第'+(key+1)+'天卖出，收益'+(value-prev_arr_min))
47                             }
48                         }
49                     })
50                 },
51                 findIndx(arr,num){
52                     let index_arr = []
53                     console.log(arr)
54                     console.log(num)
55                     _.forEach(arr,function(value, key){
56                         console.log(key)
57                         if(parseInt(value)==num){
58                             console.log(key)
59                             index_arr.push(key+1)
60                         }
61                     })
62                     return index_arr
63                 }
64             },
65             
66         })
67     </script>
68 </body>
69 </html>
View Code

 

 

题目三：

传入一个带“(”和“)”括号的字符串，删除最少的括号，使得输入有效，返回所有可能的结果。

例：
输入: "()())()"
输出: ["()()()", "(())()"]


输入: "(a)())()"
输出: ["(a)()()", "(a())()"] 

# Py 笨方法（带修订，仅能去掉多余括号，不能得出更多结果）

#!/usr/bin/env python
# -*- coding:utf-8 -*-
# __author__ = "loki"


def regroup(data):
    res = []
    left_num = 0
    right_num = 0
    for i in data:
        if i == "(":
            left_num += 1
        else:
            right_num += 1
        res.append(i)

    while 1:
        if left_num > right_num:
            res.pop(res.index("("))
            left_num -= 1
            continue
        elif left_num < right_num:
            res.pop(res.index(")"))
            right_num -= 1
            continue
        else:
            break

    return "".join(res)


def main():
    user_input = "()())()"
    print(user_input)
    print("fix--> ", regroup(user_input))


if __name__ == '__main__':
    main()
View Code

 

# Js 

 1     var set=[];
 2 
 3     var input;
 4 
 5 
 6     //去多余的括号
 7     function test5(s){
 8         input = s;
 9         var left = 0, right = 0;
10         for (var i = 0; i < s.length; i++) {
11             var  c = s.charAt(i);
12             if (c == '(') {
13                 left++;
14             } else if (c == ')') {
15                 if (left == 0) {
16                     right++;
17                 } else {
18                     left--;
19                 }
20             }
21         }
22         removeInvalidParentheses(0, "", 0, 0, left, right);
23 
24         var res=unique1(set);
25 
26         document.write("输入值:\""+s+"\"&nbsp;&nbsp;;&nbsp;&nbsp;");
27         document.write("输出值:[");
28         for(var j = 0;j < res.length; j++){
29             if(j==res.length-1){
30                 document.write("\""+res[j]+"\"");
31             }else{
32                 document.write("\""+res[j]+"\",");
33             }
34 
35         }
36         document.write("]<br/>");
37 
38 
39     }
40 
41     //去重
42     function unique1(arr){
43         var hash=[];
44         for (var i = 0; i < arr.length; i++) {
45             if(hash.indexOf(arr[i])==-1){
46                 hash.push(arr[i]);
47             }
48         }
49         return hash;
50     }
51 
52     function removeInvalidParentheses(index,valid,leftCount,rightCount,leftRem,rightRem){
53         if (index == input.length) {
54             if (leftRem == 0 && rightRem == 0) {
55                 set.push(valid);
56             }
57             return;
58         }
59         var c = input.charAt(index);
60         if (c == '(') {
61             if (leftRem > 0) {
62                 removeInvalidParentheses(index + 1, valid, leftCount, rightCount, leftRem - 1, rightRem);
63             }
64             removeInvalidParentheses(index + 1, valid + c, leftCount + 1, rightCount, leftRem, rightRem);
65         } else if (c == ')') {
66             if (rightRem > 0) {
67                 removeInvalidParentheses(index + 1, valid, leftCount, rightCount, leftRem, rightRem - 1);
68             }
69             if (rightCount < leftCount) {
70                 removeInvalidParentheses(index + 1, valid + c, leftCount, rightCount + 1, leftRem, rightRem);
71             }
72         } else {
73             removeInvalidParentheses(index + 1, valid + c, leftCount, rightCount, leftRem, rightRem);
74         }
75 
76     }
77 
78     test5("(a)()))(()");
View Code

 

 

题目四：

城市的天际线是从远处观看该城市所有建筑物形成的外部轮廓，输入所有建筑物的X,Y,Height坐标，返回天际线关键点。

例：
输入：buildings = [[2,9,10],[3,7,15],[5,12,12],[15,20,10],[19,24,8]]
输出：[[2,10],[3,15],[7,12],[12,0],[15,10],[20,8],[24,0]]

提示：
1、 每个关键点较上个关键点的X,Height均发生变化。
2、 城市天际线问题 网上有原题

 

# Js

<script>
    function test6(arr){
        var res;
        document.write("输入值:"+print_arr2(arr)+"&nbsp;&nbsp;;&nbsp;&nbsp;");
        if(arr.length==0){
            document.write("输出值:[]&nbsp;&nbsp;;&nbsp;&nbsp;<br/>");
        }else{
            res=getSkyline(arr);
            document.write("输出值:"+print_arr2(res)+"&nbsp;&nbsp;;&nbsp;&nbsp;<br/>");
        }


    }

    //输出二位数组
    function print_arr2(res){
        var str="[";
        for(var i = 0;i < res.length; i++){
            str=str+"[";
            for(var j = 0;j < res[i].length; j++){
                if(j==res[i].length-1){
                    str=str+res[i][j];
                }else{
                    str=str+res[i][j]+",";
                }
            }
            if(i==res.length-1){
                str=str+"]";
            }else{
                str=str+"],";
            }
        }
        str=str+"]";
        return str;
    }

    function getSkyline(buildings){
        var height = [];
        var res = [];
        var line= [];
        var pre = 0;
        var cur = 0;
        //将矩阵的左右边界以及其高度放入数组中，为了区分左右边界，将高度分为正负值
        //即可
        for(var i=0;i<buildings.length;i++){
            var tmp=[];
            var tmp1=[];
            tmp[0] = buildings[i][0];
            tmp[1] = -buildings[i][2];
            height.push(tmp);
            tmp1[0] = buildings[i][1];
            tmp1[1] = buildings[i][2];
            height.push(tmp1);
        }
        //将数组按照横坐标进行排序
        height.sort(function(a,b){return (a[0]-b[0]);});
        //将0加入multiset，为了能够在遍历的过程中可以得到两个不重叠矩阵的高度为0的
        //坐标位置
        line.push(0);
        //遍历所有的矩阵的边界状态
        for(var j=0; j<height.length; j++){
            if(height[j][1]<0){
                line.push(-height[j][1]);
            }else{
                line.splice(line.indexOf(height[j][1]),1);
            }
            line.sort(function(a,b){return a-b;});
            cur = line[line.length-1];
            if(cur!=pre){
                if(j>0&&res[res.length-1][0]==height[j][0]){
                    if(cur>pre){
                        res[res.length-1][1]=cur;
                    }
                }else{
                    res.push([height[j][0], cur]);
                }

                pre = cur;
            }
        }

        return res;
    }
    test6([[2,9,10],[2,7,15],[5,12,12],[5,12,17],[15,20,10],[19,24,8]]);
    test6([[2,9,10]]);
    test6([[2,9,10],[3,7,15]]);
    test6([[2,9,10],[3,7,15],[5,12,12],[15,20,10],[19,24,8]]);
    test6([[2,9,10],[2,7,15],[5,12,12],[15,20,10],[19,24,8]]);
    test6([[2,9,18],[2,7,15],[5,12,12],[15,20,10],[19,24,8]]);
</script>
View Code

 

 

题目五：编写一个函数来验证输入的字符串是否是有效的 IPv4 或 IPv6 地址。

示例 1：
输入：IP = "172.16.254.1"
输出："IPv4"

示例 2：
输入：IP = "2001:0db8:85a3:0:0:8A2E:0370:7334"
输出："IPv6"

示例 3：
输入：IP = "256.256.256.256"
输出："Neither"

示例 4：
输入：IP = "2001:0db8:85a3:0:0:8A2E:0370:7334:"
输出："Neither"

示例 5：
输入：IP = "x1.4.5.6"
输出："Neither"

 

# Js（带界面）

 1 <!DOCTYPE html>
 2 <html lang="zh">
 3 <head>
 4     <meta charset="UTF-8">
 5     <meta name="viewport" content="width=device-width, initial-scale=1.0">
 6     <meta http-equiv="X-UA-Compatible" content="ie=edge">
 7     <title></title>
 8     <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js" type="text/javascript" charset="utf-8"></script>
 9     <script src="https://cdn.jsdelivr.net/npm/vue/dist/vue.js"></script>
10 </head>
11 <body>
12     <div id="app">
13         <span>ipv4:192.168.1.1</span><br>
14         <span>ipv6:2001:0db8:85a3:0:0:8A2E:0370:7334</span><br>
15         <input type="text" v-model="ip" style="width: 550px;">
16         <span style="color: red;" v-if="!flag">输入正确的ip地址</span>
17         <span style="color: green;" v-if="flag">正确的ip地址</span>
18     </div>
19     <script type="text/javascript">
20         let app = new Vue({
21             el: "#app",
22             data: {
23                 ip: '',
24                 flag: false
25             },
26             watch: {
27                 ip(newValue, oldValue) {
28                     ip = this.ip
29                     console.log(this.isIPv4(ip))
30                     console.log(this.isIPv6(ip))
31                     if(this.isIPv4(ip) || this.isIPv6(ip))    
32                      { 
33                         this.flag = true
34                      }else{
35                          this.flag = false
36                      }
37                 }
38             },
39             methods: {
40                 isIPv6(str){
41                     if(str.indexOf(":") >= 0){//需要加上判断：号是否存在，因为如果不存在冒号，就没必要走进来判断；同时如果没有冒号，会报错：cann't read "length" of null
42                         return str.match(/:/g).length<=7 && /::/.test(str) ? /^([\da-f]{1,4}(:|::)){1,6}[\da-f]{1,4}$/i.test(str) : /^([\da-f]{1,4}:){7}[\da-f]{1,4}$/i.test(str);
43                     }
44                 },
45                 isIPv4(str){
46                     var re=/^(\d+)\.(\d+)\.(\d+)\.(\d+)$/;//正则表达式    
47                     if(re.test(str)){    
48                         if( RegExp.$1<256 && RegExp.$2<256 && RegExp.$3<256 && RegExp.$4<256)  
49                         return true; 
50                     };
51                 }
52             },
53             
54         })
55     </script>
56 </body>
57 </html>
View Code

# Js

  1     function test(){
  2         var array1 = [1,2,3];
  3         var array2 = [2,7,8];
  4         var arr =[array1,array2];
  5         var obj = {};
  6         arr = arr
  7             .reduce((a, b) => a.concat(b), [])
  8             .sort((a, b) => b - a);
  9         for (var i=0;i<arr.length;i++) {
 10             document.write(arr[i]+"&nbsp");
 11         }
 12 
 13     }
 14     function test2(str){
 15         document.write("输入:"+str+"&nbsp;<br/>");
 16         //截取纯数字字符串
 17         var str_arr=str.match(/\d+/g);
 18         //替换每部分得字符串
 19         var str1 = str;
 20         for(var i=0;i<str_arr.length;i++){
 21             if(i==0){
 22                 var str1 =str1.replace(str_arr[i],parseInt(str_arr[i].split('').reverse().join('')).toString());
 23             }else{
 24                 var str1 = str1.replace(str_arr[i],str_arr[i].split('').reverse().join(''));
 25             }
 26 
 27         }
 28         document.write("输出:"+str1+"<br/>");
 29     }
 30     function test3(ip){
 31         if(isIPv6(ip)){
 32             document.write("IPv6<br/>");
 33         }else if(isIPv4(ip)){
 34             document.write("IPv4<br/>");
 35         }else{
 36             document.write("Neither<br/>");
 37         }
 38     }
 39 
 40     function isIPv6(tmpstr)
 41     {
 42         //CDCD:910A:2222:5498:8475:1111:3900:2020
 43         var patrn=/^([0-9a-f]{1,4}:){7}[0-9a-f]{1,4}$/i;
 44         var r=patrn.exec(tmpstr)
 45         if(r)
 46         {
 47             return true;
 48         }
 49         if(tmpstr=="::"){
 50             return true;
 51         }
 52         //F:F:F::1:1 F:F:F:F:F::1 F::F:F:F:F:1格式
 53         patrn=/^(([0-9a-f]{1,4}:){0,6})((:[0-9a-f]{1,4}){0,6})$/i;
 54         r=patrn.exec(tmpstr);
 55         if(r)
 56         {
 57             var c=cLength(tmpstr);
 58             if(c<=7 && c>0)
 59             {
 60                 return true;
 61             }
 62         }
 63         //F:F:10F::
 64         patrn=/^([0-9a-f]{1,4}:){1,7}:$/i;
 65         r=patrn.exec(tmpstr);
 66         if(r)
 67         {
 68             return true;
 69         }
 70         //::F:F:10F
 71         patrn=/^:(:[0-9a-f]{1,4}){1,7}$/i;
 72         r=patrn.exec(tmpstr);
 73         if(r)
 74         {
 75             return true;
 76         }
 77         //F:0:0:0:0:0:10.0.0.1格式
 78         patrn=/^([0-9a-f]{1,4}:){6}(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/i;
 79         r=patrn.exec(tmpstr);
 80         if(r)
 81         {
 82             if(r[2]<=255 && r[3]<=255 &&r[4]<=255 && r[5]<=255 )
 83                 return true;
 84         }
 85         //F::10.0.0.1格式
 86         patrn=/^([0-9a-f]{1,4}:){1,5}:(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/i;
 87         r=patrn.exec(tmpstr);
 88         if(r)
 89         {
 90             if(r[2]<=255 && r[3]<=255 &&r[4]<=255 && r[5]<=255 )
 91                 return true;
 92         }
 93         //::10.0.0.1格式
 94         patrn=/^::(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/i;
 95         r=patrn.exec(tmpstr);
 96         if(r)
 97         {
 98             if(r[1]<=255 && r[2]<=255 &&r[3]<=255 && r[4]<=255)
 99                 return true;
100         }
101         return false;
102     }
103 
104     function isIPv4(str)
105     {
106         var match = str.match(/^(\d+)\.(\d+)\.(\d+)\.(\d+)$/);
107         return match != null &&
108             match[1] <= 255 && match[2] <= 255 &&
109             match[3] <= 255 && match[4] <= 255;
110     }
111 
112 
113     test3("172.16.254.1");
114     test3("2001:0db8:85a3:0:0:8A2E:0370:7334");
115     test3("256.256.256.256");
116     test3("2001:0db8:85a3:0:0:8A2E:0370:7334:");
117     test3("x1.4.5.6");
View Code

# Js（简洁版）

1 <script>
2 var validIPAddress = function(IP) {
3     var ipv4 = /^((\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5]))\.){4}$/;
4     var ipv6 = /^(([\da-fA-F]{1,4}):){8}$/
5     return ipv4.test(IP + ".") ? "IPv4" : ipv6.test(IP + ":") ? "IPv6" : "Neither";
6 }
7 
8 document.write(validIPAddress('192.168.1.255'))
9 </script>
View Code

  

 

题目六：写一个JS函数，传入任意有符号数字，输出每位数字翻转结果，符号不翻转，小数点前后分别翻转。

例：
输入：-361.210 输出：-163.012
输入：120 输出：21

 

#Js

 1 <!DOCTYPE html>
 2 <html lang="zh">
 3 <head>
 4     <meta charset="UTF-8">
 5     <meta name="viewport" content="width=device-width, initial-scale=1.0">
 6     <meta http-equiv="X-UA-Compatible" content="ie=edge">
 7     <title></title>
 8     <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js" type="text/javascript" charset="utf-8"></script>
 9 </head>
10 <body>
11     <script type="text/javascript">
12         let num_1 = '-361.210'
13         let num_2 = '120'
14         function revers_num(num_1){
15             num_1 = num_1.toString() 
16             let arr = num_1.split('.')
17             let str = ''
18             let flag = 1
19             let arr_sp = arr[0].split('')
20             let arr_sp_h = _.head(arr_sp)
21             // console.log(arr_sp_h)
22             if(arr_sp_h=='-'){
23                 arr_sp = _.drop(arr_sp)
24                 // console.log(arr_sp)
25                 flag = 0            
26             }
27             arr[0] = _.join(_.concat(_.reverse(arr_sp)),'')
28             // console.log(arr[0])
29             str = flag?arr[0]:'-'+arr[0]
30             if(arr.length>1){
31                 arr[1] = _.join(_.concat(_.reverse(arr[1].split(''))),'')
32                 str += '.'+arr[1]
33             }
34             console.log(parseFloat(str))
35             document.write(parseFloat(str))
36             document.write('<br>')
37         }
38         revers_num(num_1);
39         revers_num(num_2);
40     </script>
41 </body>
42 </html>
View Code

 

 

题目七：写一个JS函数，传入任意两个纯数字内容1维数组，合并成一个数组并按元素值大小排倒叙后输出该数组。
例：
输入：array1 = [1,2,3], array2 = [2,7,8]
输出：8,7,3,2,2,1

# Js

1           function so(arr1,arr2){
2             let arr=arr1.concat(arr2);
3             arr.sort(function(a,b){
4                 return b-a
5             })
6             return arr
7           }
8           console.log(so([1,2,3],[2,7,8]))
View Code

# Js

1     var mycars1 = [1,2,3];
2     var mycars2 = [2,7,8];
3     mycars2.forEach((res) => {
4         mycars1.push(res);
5     });
6     var x=mycars1.sort(function(a, b) {
7         return b - a
8     });
9     document.write(x);
View Code

# Js

 1     function test(){
 2 
 3         var array1 = [1,2,3];
 4         var array2 = [2,7,8];
 5         var arr =[array1,array2];
 6         var obj = {};
 7 
 8         arr = arr
 9             .reduce((a, b) => a.concat(b), [])
10             .sort((a, b) => b - a); // 如果需要从小到大排序加上这个
11 
12         console.log(arr);
13     }
14     test();
View Code

 

 

题目八：

热身题目：写一个JS函数，生成99乘法表。
1*1=1
1*2=2 2*2=4
1*3=3 2*3=6 3*3=9
.....

# Py for 循环版本

for i in range(1, 10):
    for j in range(1, i+1):
        print(j, "*", i, "=", i*j, end=" ")
    print("")
View Code

# Js 

 1     function test(){
 2         for(var i=1;i<=9;i++){
 3                      document.write("<br>")
 4             for(var j=1;j<=i;j++){
 5                 sum = i * j;
 6                 document.write(j ,"*",i ,"=",sum,"   ");
 7             }
 8             
 9         }
10 
11     }
12 test();
View Code

 

# Py while 循环版本

n = 1
res = 1
while n <= 9:
    i = 1
    while i <= n:
        res = i * n
        print('%d*%d=%d' % (i, n, res), end=' ')
        i = i+1
    print('')
    n = n + 1
View Code

 

# Js 带表格边框

 1 <!doctype html>
 2 <html lang="en">
 3  
 4     <head>
 5         <meta charset="UTF-8">
 6         <title>Document</title>
 7         <!-- CSS样式 -->
 8         <style type="text/css">
 9             td {
10                 border: blue 1px solid;
11             }
12         </style>
13         <!-- JS实现 -->
14         <script type="text/javascript">
15             document.write("99乘法表");
16             document.write("<br />");
17             document.write("<table algin='center'>");
18             for (var i = 1; i <= 9; i++) {
19                 document.write("<tr>");
20                 for (var j = 1; j <= i; j++) {
21                     document.write("<td>" + j + "*" + i + "=" + (j * i) + "</td>");
22                 }
23                 document.write("</tr>");
24             }
25             document.write("</table>");
26         </script>
27     </head>
28  
29     <body>
30     </body>
31  
32 </html>
View Code

 

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