_.unzipWith(array, [iteratee=_.identity])

_.unzipWith(array, [iteratee=_.identity])

var zipped = _.zip([1, 2], [10, 20], [100, 200]);
// => [[1, 10, 100], [2, 20, 200]]
 
_.unzipWith(zipped, _.add);
// => [3, 30, 300]

import map from './map.js'
import unzip from './unzip.js'

/**
 * This method is like `unzip` except that it accepts `iteratee` to specify
 * how regrouped values should be combined. The iteratee is invoked with the
 * elements of each group: (...group).
 *
 * @since 3.8.0
 * @category Array
 * @param {Array} array The array of grouped elements to process.
 * @param {Function} iteratee The function to combine
 *  regrouped values.
 * @returns {Array} Returns the new array of regrouped elements.
 * @example
 *
 * const zipped = zip([1, 2], [10, 20], [100, 200])
 * // => [[1, 10, 100], [2, 20, 200]]
 *
 * unzipWith(zipped, add)
 * // => [3, 30, 300]
 */
//和unzip方法类似，多接收一个iteratee参数，在逆转zip操作之后对结果数组调用iteratee处理处最终结果
function unzipWith(array, iteratee) {
  if (!(array != null && array.length)) {//如果数组为空或者数组没有长度，返回空数组
    return []
  }
  const result = unzip(array)//调用unzip获取到zip逆转后的结果
  return map(result, (group) => iteratee.apply(undefined, group))
  //遍历结果数组，用iteratee处理生成最终的结果
}

export default unzipWith