【74.00%】【codeforces 747A】Display Size
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly n pixels.
Your task is to determine the size of the rectangular display — the number of lines (rows) of pixels a and the number of columns of pixels b, so that:
there are exactly n pixels on the display;
the number of rows does not exceed the number of columns, it means a ≤ b;
the difference b - a is as small as possible.
Input
The first line contains the positive integer n (1 ≤ n ≤ 106) — the number of pixels display should have.
Output
Print two integers — the number of rows and columns on the display.
Examples
input
8
output
2 4
input
64
output
8 8
input
5
output
1 5
input
999999
output
999 1001
Note
In the first example the minimum possible difference equals 2, so on the display should be 2 rows of 4 pixels.
In the second example the minimum possible difference equals 0, so on the display should be 8 rows of 8 pixels.
In the third example the minimum possible difference equals 4, so on the display should be 1 row of 5 pixels.
【题目链接】:http://codeforces.com/contest/747/problem/A
【题解】
暴力枚举n的因子x
看看n/x是不是满足x<=n/x
然后记录那个差最小的就好.
【完整代码】
#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define rei(x) scanf("%d",&x)
#define rel(x) scanf("%I64d",&x)
typedef pair<int,int> pii;
typedef pair<LL,LL> pll;
//const int MAXN = x;
const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
const double pi = acos(-1.0);
int n;
int ma = 1e7,ansa,ansb;
int main()
{
//freopen("F:\\rush.txt","r",stdin);
rei(n);
rep1(i,1,n)
if ((n%i)==0)
{
int a = n/i;
int b = i;
if (a <= b)
{
if (b-a<=ma)
{
ma = b-a;
ansa = a;
ansb = b;
}
}
}
cout << ansa<<" "<<ansb<<endl;
return 0;
}
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