[LeetCode] Ugly Number II

Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 1, 2, 3, 4, 5, 6, 8, 9, 10, 12 is the sequence of the

Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 1, 2, 3, 4, 5, 6, 8, 9, 10, 12 is the sequence of the first 10 ugly numbers.

Note that 1 is typically treated as an ugly number.

Hint:

The naive approach is to call isUgly for every number until you reach the nth one. Most numbers are not ugly. Try to focus your effort on generating only the ugly ones. An ugly number must be multiplied by either 2, 3, or 5 from a smaller ugly number. The key is how to maintain the order of the ugly numbers. Try a similar approach of merging from three sorted lists: L1, L2, and L3. Assume you have Uk, the kth ugly number. Then Uk+1 must be Min(L1 * 2, L2 * 3, L3 * 5).

见题目中的提示，主要就是维持一个丑数序列，一个丑数一定是序列中比它小的丑数乘以2,3或5的结果。

int ugly = Math.min(Math.min(num[n2] * 2, num[n3] * 3), num[n5] * 5); num[i++] = ugly; if (ugly == num[n2] * 2) { n2++; if (ugly == num[n3] * 3) { n3++; if (ugly == num[n5] * 5) { n5++; return num[n - 1]; }
LeetCode 306. Additive Number 累加数是一个字符串，组成它的数字可以形成累加序列。 一个有效的累加序列必须至少包含 3 个数。除了最开始的两个数以外，字符串中的其他数都等于它之前两个数相加的和。 给定一个只包含数字 0 - 9 的字符串，编写一个算法来判断给定输入是否是累加数。 说明: 累加序列里的数不会以 0 开头，所以不会出现 1, 2, 03 或者 1, 02, 3 的情况。