LeetCode:Pow(x, n)
Java实现 LeetCode 50 Pow（x,n）
50. Pow(x, n) 实现
日期 2023-06-12 10:48:40![[LeetCode] Power of Three | Power of Two](/scriptcss/images/63.png)
[LeetCode] Power of Three | Power of Two
Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it
日期 2023-06-12 10:48:40
LeetCode Pow(x, n)-简单粗暴法解决
实现 pow(x, n) ，即计算 x 的 n 次幂函数（即，xn）。 示例 1： 输入：x = 2.00000, n = 10 输出：1024.00000 示例 2： 输入：x = 2.10000, n = 3
日期 2023-06-12 10:48:40leetcode 231. Power of Two
Given an integer, write a function to determine if it is a power of two. class Solution(object): def isPowerOfTwo(self, n): """ :type n: int :rtype: bool """
日期 2023-06-12 10:48:40