143. Reorder List**
leetcode 之Reorder List（25）
找到中间结点，将后半部分反转接入即可。 ListNode *reoderList(ListNode* head) { if (head == nullptr || head->next == nullptr)return head; //找到中间结点的方法很巧妙 ListNode *slow = head, *
日期 2023-06-12 10:48:40
Flutter ReorderableListView 可拖拽的列表
import 'package:flutter/material.dart'; import 'dart:math' as math; void main() => runApp(MyApp()); class MyApp extends StatelessWidget { @override Widget build(BuildContext context) {
日期 2023-06-12 10:48:40![[LeetCode] Reorder List](/scriptcss/images/05.png)
[LeetCode] Reorder List
Given a singly linked list L: L0→L1→…→Ln−1→LnL_0→L_1→…→L_{n-1}→L_n, reorder it to: L0→Ln→L1→Ln−1→L2→Ln−2→…L_0→L_n→L_1→L_{n-1}→L_2→L_{n-2}→… You must do this in-place without altering the Given a
日期 2023-06-12 10:48:40【LeetCode】Reorder List 解题报告
Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3
日期 2023-06-12 10:48:40Reorder List -- leetcode
Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3
日期 2023-06-12 10:48:40Leetcode: Reorder List && Summary: Reverse a LinkedList
Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3,4}, reorder it to {1,4
日期 2023-06-12 10:48:40![[LeetCode] Reorder List](/scriptcss/images/01.png)
[LeetCode] Reorder List
Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}
日期 2023-06-12 10:48:40Reorder List @LeetCode
思路就是： 1 用快慢指针找到中间节点 2 翻转中间节点后一个元素到最后一个元素区间的所有元素 3 断开前半段和翻转后的后半段元素 4 把前半段和翻转后的后半段元素以交叉的方式合并起来 5 特殊处理输入为空，只有一个元素和只有两个元素的corner case，就是多加几个if...return 感想：可以看出翻转链表实在是非常重要，是做很多题目的基础。还有merge的思想也很重要！ &n
日期 2023-06-12 10:48:40
【LeetCode】143. Reorder List
Reorder List Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example,Given {
日期 2023-06-12 10:48:40[LeetCode] Reorder List 链表重排序
Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You may not modify the values in the list's nodes, only nodes itself may be change
日期 2023-06-12 10:48:40