LeetCode Word Break
【leetcode】Word Break（python）
思路是这种。我们从第一个字符開始向后依次找，直到找到一个断句的地方，使得当前获得的子串在dict中，若找到最后都没找到。那么就是False了。 在找到第一个后，接下来找下一个断句处，当然是从第一个断句处的下一个字符開始找连续的子串，可是这时与第一个就稍有不同。比方说word=‘ab’， dict={ 'a', ab', ...},在找到a后，接下来处理的是b。我们发现b不在dict中，可是我
日期 2023-06-12 10:48:40Leetcode: Word Break II
Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, given s = "cat
日期 2023-06-12 10:48:40
Leetcode: Word Break
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Note: Th
日期 2023-06-12 10:48:40[LeetCode] Word Break II
Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences.
日期 2023-06-12 10:48:40[LeetCode] Word Break
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens =&n
日期 2023-06-12 10:48:40leetcode Word Break I II 算法分析
http://blog.csdn.net/cs_guoxiaozhu/article/details/14104789 http://oj.leetcode.com/problems/word-break-ii/
日期 2023-06-12 10:48:40【LeetCode】139. Word Break
Word Break Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, give
日期 2023-06-12 10:48:40【LeetCode】140. Word Break II
Word Break II Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, giv
日期 2023-06-12 10:48:40【LeetCode】Word Break 解题报告
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, given s&nb
日期 2023-06-12 10:48:40
【LeetCode-面试算法经典-Java实现】【139-Word Break（单词拆分）】
【139-Word Break（单词拆分）】 【LeetCode-面试算法经典-Java实现】【全部题目文件夹索引】 原题 Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one
日期 2023-06-12 10:48:40![[LeetCode]Word Break 特里](/scriptcss/images/61.png)
[LeetCode]Word Break 特里
意甲冠军：推断字符串给定的字符串是否构成词典。 来推断目标字符串相匹配整个字典。我们需要来推断目标字符串的每个前缀开始的下一场比赛，这需要匹配目标字符串的成功，所有前缀的枚举。 class TrieNode{//from http://www.cnblogs.com/x1957/p/3492926.html public: TrieNode* ch[26];//char指针数组
日期 2023-06-12 10:48:40[LeetCode] Word Break II 拆分词句之二
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each
日期 2023-06-12 10:48:40leetcode 139. Word Break 单词拆分(中等)
一、题目大意 标签: 动态规划 https://leetcode.cn/problems/word-break 给你一个字符串 s 和一个字符串列表 wordDict 作为字典。请你判断是否可以利用字典中出现的单词拼接
日期 2023-06-12 10:48:40